You are given an array of N integers (where A[i] denotes ith element of the array) . Each A[i] forms an arithmetic progression in which the first term is same as the common difference and is equal to A[i]. Now all the N arithmetic progressions are combined together to form a new set S.
Your task is to find the Kth element of set S.
First line contains T (no. of testcases).
First line of every testcase contains two integers N (no. of integers in array) and K .
Second line of testcase contains N integers of Array.
1<=T<=5
1<=N<=10
1<=A[i]<=50
1<=K<=10^13
Note: Every A[i] is prime number and all are pairwise distinct .
Note: All elements in a set are distinct and in sorted order.
Output the kth element in the set for each test case in a separate line.
As N=2, so there are 2 arithmetic progressions. first term and common difference of first A.P is 2 and first term and common difference of second A.P is 3. thus set S contains { 2,3,4,6,8,9,10,12,14,15,16,18,20...... }. So, 10th element in this set is 15.