SOLVE
LATER
Given \(2*N\) pebbles of N different colors, where there exists exactly 2 pebbles of each color, you need to arrange these pebbles in some order on a table. You may consider the table as an infinite 2D plane.
The pebbles need to be placed under some restrictions :
In short consider you place a pebble of color i at co-ordinate \((X,Y)\). Here, it is necessary that \((i=X)\) , \((i!=Y)\) there exist some other pebbles of color equal to Y.
Now, you need to enclose this arrangement within a boundary , made by a ribbon. Considering that each unit of the ribbon costs M, you need to find the minimum cost in order to make a boundary which encloses any possible arrangement of the pebbles. The ribbon is sold only in units (not in further fractions).
Input Format:
First line consists of an integer T denoting the number of test cases. The First line of each test case consists of two space separated integers denoting N and M.
The next line consists of N space separated integers, where the \(i^{th}\) integer is \(A[i]\), and denotes that we have been given exactly 2 pebbles of color equal to \(A[i]\). It is guaranteed that \(A[i]!=A[j]\), if \(i!=j\)
Output Format:
Print the minimum cost as asked in the problem in a separate line for each test case.
Constraints:
\( 1 \le T \le 50 \)
\( 3 \le N \le 10^5 \)
\( 1 \le M \le 10^5 \)
\( 1 \le A[i] \le 10^6 \) ; where \(1 \le i \le N\)
An arrangement can be :
Pebbles of color 1: (1,2) , (1,3)
Pebbles of color 2: (2,1) , (2,3)
Pebbles of color 3: (3,1) , (3,2)
The length of ribbon required is= 6.828427125
The cost of ribbon is = 7*5=35 as we have to buy ribbon in units.
This arrangement's boundary covers all possible arrangements.