SOLVE
LATER
Everyone knows that some special Pikachus hate evolving into Raichus. (The legend says because Raichu is ugly, and Pikachu looks good!)
The question is how do we find these special Pikachus who hate evolution? The crazy Poke'mon trainer Ash Catch'Em has derived a random algorithm, which is completely wrong, but since he's your friend, you've to humor him and his crazy algorithms.
He thinks if you are given $$N$$ Pikachus in an array, A_{1},A_{2} ... A_{N}, where each Pikachu is denoted by an integer. The total number of unique pairs (A_{i},A_{j}) where i < j is the number of Pikachus who hate evolution.
Input format:
The first line will consist of a single integer $$N$$. The second line consists of $$N$$ integers A_{1},A_{2} ... A_{N}.
Output format:
Output the total number of unique pairs (A_{i},A_{j}) that can be formed, which will also be the number of special Pikachus.
Constraints:
1 ≤ $$N$$ ≤ 2 * 10^{5}
1 ≤ $$A$$_{i} ≤ 10^{9}
Reference:
All the possible pairs are (1,1),(1,2) , (1,3) , (2,1), (2,2), (2,3).