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Holi And Colorful houses
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Basic Programming, Basics of Implementation, Easy, Implementation

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This Holi, Monk wants to distribute sweets to the houses of his colony. The houses of the colony are present in a circular order (i.e. house 1 and house N are adjacent to each other).

Kids love to play with colors but currently there is a supply of only 2 types of colors (Red represented by R and Green represented by G). Due to festive season each of the kids have colored their houses with either green or red color.

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Monk is given a task of distributing sweets Q number of times. Every time he is asked to travel from \(x^{th}\) house to \(y^{th}\) house to distribute the sweets.
The distribution strategy is that he starts from \(x^{th}\) house and he has to give 1 sweet to a house only when he travels from green house to a red house or vice-versa. Monk can travel from \(x^{th}\) house to \(y^{th}\) house either in clockwise direction or in anti-clockwise direction.
Monk wants your help to find the minimum number of sweets he should carry to complete his journey.

Input Format

First line contains an integer T denoting the number of test cases.

Each test case contains an integer N and Q.

Next line contains a string S (representing the house colors) of length N.

Then Q lines follow, each containing 2 integers x and y.

Output Format

For each test case print Q lines containing the minimum number of sweets he must carry with himself.

Input Constraints

\(1 \le T \le 100 \)

\(1 \le N,Q \le 1000 \)

\(1 \le x,y \le N \)

S consists of only letters 'G' and 'R'

SAMPLE INPUT
2
5 2
RRRGG
1 5
3 2
5 2
GGRGG
2 5
3 1
SAMPLE OUTPUT
1
0
0
1
Explanation

Case 1:

For 1st query, if we travel in the direction 1->2->3->4->5, we need only one sweet . If we travel in the direction 1->5, we need only one sweet. So he has to carry only 1 sweet.

For 2nd query, if we travel in the direction 3->4->5->1->2, we need two sweets. If we travel in the direction 3->2, we need no sweets. So he has to carry 0 sweets.

Case 2:

For 1st query house, 2 and 5 can be travelled using path 2->1->5 without any change of colors so he has to carry 0 sweets.

For 2nd query house 3 and 1 can be travelled using path 3->2->1 with a change of color so he has to carry 1 sweet.

Time Limit: 1.0 sec(s) for each input file.
Memory Limit: 256 MB
Source Limit: 1024 KB
Marking Scheme: Marks are awarded when all the testcases pass.
Allowed Languages: Bash, C, C++, C++14, Clojure, C#, D, Erlang, F#, Go, Groovy, Haskell, Java, Java 8, JavaScript(Rhino), JavaScript(Node.js), Julia, Kotlin, Lisp, Lisp (SBCL), Lua, Objective-C, OCaml, Octave, Pascal, Perl, PHP, Python, Python 3, R(RScript), Racket, Ruby, Rust, Scala, Swift, Swift-4.1, TypeScript, Visual Basic

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This Problem was Asked in

HackerEarth

Challenge Name

March Easy '18

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